WebJan 31, 2024 · Area of trapezium = 1/2 × (sum of parallel sides) × height Calculation: ABCD is a trapezium AD II BC, AB = 5 cm, BC = 11 cm, AD = 7 cm, DA is produced to a point F such that AF = 3 cm and BF perpendicular to DF. In triangle BFA, BF 2 = AB 2 - AF 2 BF 2 = 5 2 - 3 2 BF 2 = 16 cm BF = 4 cm Area of trapezium = 1/2 × (sum of parallel sides) × height WebIn quadrilateral ABCD, Angle A+D = 90 , Prove that AC2 + BD2 = AD2 + BC2 OM Education you Tube channel will provide all the videos of Classes 10th and 9th in which usually a student faces...
ABCD is a trapezium in which AB is parallel to CD Then AC2 + BD2 …
Web1. In a trapezium ABCD, if AB CD, then AC2 + BD2 is equal to: 1. BC2 + AD2 + 2AB. CD 2. AB2 + CD2 + 2AD. BC 3. AB2 + CD2 + 2AB. CD 4. Insufficient data Answer & Solution … WebDec 6, 2024 · Let A B = b , C D = a where a < b. Let S be the area of trapezium A B C D. It is given that [ Δ B O C] = 2 S 9. Find the value of b a. Related Question :- A B C D is a … florinia\\u0027s gym answeres poekmon reborn
Solved 2. The trapezium ABCD is shown below. Determine the
WebIn a trapezium ABCD If AB∥CD, thee AC2+BD2is equal to: A BC2+AD2+2AB.CD B AB2+CD2+2AD.BC C AB2+CD2+2AB.CD D BC2+AD2+2BC.AD Viewed by: 529students Solutions (1) (a): In ΔABD,∠A is acute. So BD2=AD2+ AB2−2AB.AQ ---(i) In ΔABC,∠B is acute. WebMar 29, 2024 · Given: where AD BC To Prove:- AB2 + CD2 = BD2 + AC2 Proof: Since AC BD ADC = ADB = 90 Doing (1) (2) AB2 AC2 = (AD2 + BD2) (AD2 + CD2) AB2 AC2 = AD2 + BD2 AD2 CD2 AB2 AC2 = BD2 CD2 AB2 + CD2 = BD2 + AC2 Hence proved Next: Example 13 Important → Ask a doubt Chapter 6 Class 10 Triangles Serial order wise Examples WebIn a trapezium ABCD, if AB CD, then prove that AC²+BC²=BC²+AD²+2AB*CD? I previously showed in my answer to the original question below that for an isosceles trapezium, AC^2 … flor inmortal